Hi all!
I am new to this forum and to gene expression analysis, being this the first time I use data from the Allen Human Brain Atlas. I am trying to compare the expression of a particular gene (e.g. GRIN1) between two structures (e.g. cerebellar cortex [CbCx] and cerebellar nuclei [CbN]). For this I did the following:
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I used the Microarray data from the Allen Human Brain Atlas. I did a “Gene search” since with the “Differential search” I could not easily find a gene among all the thousands included in that search.
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I set the Heatmap resolution to “Coarse” and sorted data by structure instead of by donor.
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Following what I read in this Topic and in this other Topic I changed Color map to log2(intensity).
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I downloaded the data and worked on Excel. As recommended there, I choose the probe with the highest log2(intensity) values/warmest colors (i.e. probe A_23_P84670).
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Then, as it was also recommended there, I averaged the log2(intensity) values from all 6 donors for each one of the two structures I am interested, obtaining these results: average(CbCx)=11.0799666 and average(CbN)=11.76543333
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I calculated the difference between the averages, which, if I understand well, would give me the fold-change in gene expression between the structures, which gave me a negative value:
log2(FC) = average(CbCx)-average(CbN) = 11.0799666 - 11.76543333 = -0.68547 -
Then I calculated FC as follows, obtaining a value below 1:
FC = 2^(log2(FC)) = 2^-0.68547 = 0.62180466
Following the same steps but for another gene (GRIN2C), after calculating the difference between the averages I obtained a positive log2(FC) value:
log2(FC) = average(CbCx)-average(CbN) = 13.34336667 - 10.68195 = 2.661416667
So FC was above 1:
FC = 2^(log2(FC)) = 2^2.661416667 = 6.326539845
My doubt is what exactly this FC values (if calculated correctly) would mean, i.e. how should they be interpreted if they are below or above 1. If, for example, I take the same structure there will be no actual change in gene expression. For example, in the case of GRIN1:
log2(FC) = average(CbCx)-average(CbCx) = 13.34336667 - 13.34336667 = 0
FC = 2^(log2(FC)) = 2^0 = 1
Would a FC of 1 mean that the expression level is the same?
Thank you very much for your help!